The pH of pure water will thus be. pH = −log([H3O+]) pH = −log(10−7) = 7. Now, let's assume that you're working with a 1.0-L solution of pure water and you add some 10−8M hydrochloric acid solution. To keep calculations simple, let's assume that the volume remains unchanged upon adding this hydrochloric acid solution.
As mass / volume = molarity × molar mass, then mass / (volume × molar mass) = molarity. Substitute the known values to calculate the molarity: molarity = 5 / (1.2 × 36.46) = 0.114 mol/l = 0.114 M. You can also use this molarity calculator to find the mass concentration or molar mass. Simply type in the remaining values and watch it do all
The exact relationship depends on the activity of the hydrogen ion: pH = −log10aH+ (2) (2) p H = − log 10 a H +. Consequently, activities for hydrogen-ion in a given solution can be determined through simple pH measurements, and the activity coefficient ( γ γ) can be evaluated using the relationship. a = γC (3) (3) a = γ C.
You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Calculate the pH of solution produced by dissolving 0.001 moles of HNO3 in a liter of water. Assume complete dissociation. Select one:a. pH = 3.0 b. pH = 0.001 c. pH = 1 x 10-3 d. pH = 1 x 103. Calculate the pH of solution produced by
Calculate the pH of a buffer solution that is 1.25 M CH3NH2 and 1.00 M CH3NH3Cl. Kb = 8.85 x 10-4 and what would happen after 35.0 mL of 0.45 M HNO3 is added to 250.0 mL of the buffer solution, what would the pH of the solution be after the HNO3(aq) is added?
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calculate ph of hno3